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4.9t^2=15.4t-4.9t^2
We move all terms to the left:
4.9t^2-(15.4t-4.9t^2)=0
We get rid of parentheses
4.9t^2+4.9t^2-15.4t=0
We add all the numbers together, and all the variables
9.8t^2-15.4t=0
a = 9.8; b = -15.4; c = 0;
Δ = b2-4ac
Δ = -15.42-4·9.8·0
Δ = 237.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.4)-\sqrt{237.16}}{2*9.8}=\frac{15.4-\sqrt{237.16}}{19.6} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.4)+\sqrt{237.16}}{2*9.8}=\frac{15.4+\sqrt{237.16}}{19.6} $
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